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3=0.005x^2+x+6
We move all terms to the left:
3-(0.005x^2+x+6)=0
We get rid of parentheses
-0.005x^2-x-6+3=0
We add all the numbers together, and all the variables
-0.005x^2-1x-3=0
a = -0.005; b = -1; c = -3;
Δ = b2-4ac
Δ = -12-4·(-0.005)·(-3)
Δ = 0.94
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{0.94}}{2*-0.005}=\frac{1-\sqrt{0.94}}{-0.01} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{0.94}}{2*-0.005}=\frac{1+\sqrt{0.94}}{-0.01} $
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